science
solve for the amount of force exerted on an 8-kg ball rolling at 2m/s when it bumps into a pillow and stops in 0.5s. how mush force does the pillow exert on the ball?
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The amount of force exerted on the 8-kg ball is 16 kgm/s2. This is because the formula for force is F = m * a, and acceleration is calculated as a = ΔV/Δt. So, we have F = 8 * (2/0.5) = 16 kgm/s2. The pillow is exerting an equal and opposite amount of force on the ball. This means the pillow is exerting a force of 16 kgm/s2 on the ball. This force is necessary to slow down the ball and bring it to a stop in 0.5s.
