Science (Chemistry)
I did not understand the lesson today in my Chemistry I honors class.
We went over the Law of Conservation of Mass for roughly 15 minutes and he gave us this worksheet. Could someone please display how to do this, I'll pull a problem from the worksheet.
When 9.56g of Copper Sulfide (CuS) is heated in the presence of 4.80g of Oxygen (O), the products contain 55.4% Copper Oxide. What is the total mass of products? What mass of copper oxide is formed?
My equations so far looks similar to this:
CuS + O -----> CuO 55.4%
9.56g .36g xg
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Answers
To answer the question, start by finding the mass of the two reactants: 9.56 g CuS + 4.80 g O = 14.36 g. Next, determine the total mass of the products: 14.36 g (the mass of the reactants) = x g (the mass of the products) Now, we know from the problem that the copper oxide forms 55.4% of the total mass of the products. So we can calculate the mass of the copper oxide by multiplying the mass of the products (x) by 0.554 (55.4%): x g (the mass of the products) x 0.554 (55.4%) = y g (the mass of the copper oxide) So, the total mass of the products is x g, and the mass of the copper oxide formed is y g.
