Physics
A cylinderical brass rod with a radius of 2.10 cm and length of 1.50 m is placed in a fire with temperature of 490 deg. C. If the other end of the rod is at a temperature of 33 deg. C, what is the rate of heat transfer through the rod (ignore any heat loss from the sides of the rod).
Brass constant = 110
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Answers
The rate of heat transfer through the rod can be calculated using Fourier's Law, which states that the rate of heat flow through a material is equal to the thermal conductivity, k, multiplied by the area, A, of the cross-section of the material, multiplied by the temperature difference (ΔT) over the length of the material (L).
Therefore, the rate of heat transfer through the rod is:
Rate of heat transfer = k * A * (ΔT/L)
= 110 W/mK * (π * (2.10 cm)^2) * (490°C - 33°C) / (1.50 m)
= 122030 W
