physics
During a ski race, Kate uniformly accelerated at 3.15m/s^2 for 100meters. She then maintained this velocity for another 100m. she then uniformly decelerated at 6m/s^2 for 2 seconds. she accelerates back to her maximum velocity over the next 200meters in 16 seconds. she then travleled 1.0km at this maximum velocity
what was her maximum velocity and what distance did she travel while decelerating at 6.00m/s^2
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Answers
Kate's maximum velocity is 23.85 m/s. She traveled 12 m while decelerating at 6.00 m/s2. This is because she accelerated at 3.15 m/s2 for 100 m, maintained her velocity for another 100 m, then decelerated for 2s. The velocity is given by v=at, so the velocity after 2s of deceleration is v = 6.00 x 2 = 12 m/s. She then accelerated back to her max velocity at a rate of 3.15 m/s2 for 16s, equalling v = 3.15 x 16 = 49.6 m/s. She then traveled 1 km at her maximum velocity, which is 49.6 m/s - 12 m/s = 37.6 m/s. Therefore her maximum velocity is 23.85 m/s.
