physics
A charge of +24.3 µC is located at (4.40 m, 6.02 m) , and a charge of -13.1 µC is located at (-4.50 m, 6.75 m) . What charge must be located at (2.23 m, -3.01 m) if the electric potential is to be zero at the origin?
ANyone have any advice?
Find the distances to the center.
Potential is a scalar.
0= V1 + V2 + V3
where V1= k q1/r1 ; V2= kq2/r2 ; and V2= kq3/r3
solve for q3
Reply
Answers
The charge q3 needed at (2.23 m, -3.01 m) to bring the electric potential to zero at the origin can be calculated as follows. From the origin to the charge of +24.3 µC, the distance r1 is given by: r1=√(4.40 m-0 m)^2+(6.02 m-0 m)^2=7.31 m. From the origin to the charge of -13.1 µC, the distance r2 is given by: r2=√(-4.50 m-0 m)^2+(6.75 m-0 m)^2=8.05 m. From the origin to the charge of unknown magnitude q3, the distance r3 is given by: r3=√(2.23 m-0 m)^2+(-3.01 m-0 m)^2=3.60 m. Therefore, the electric potential at the origin is given by: 0= k (24.3 µC/7.31 m) + k(-13.1 µC/8.05 m) + kq3/3.60 m Solving for q3, we get: q3 = (-24.3 µC/7.31 m) + (13.1 µC/8
