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In mid-nineteenth century England horses were often used to pull barges along canals. The horse, naturally, trudged along a path parallel to the canal and so the rope to the barge was at an angle to the motion of the barge. If such a horse was pulling with a force of 175 N at a speed of 12.80 Km/hr and the angle of the rope with respect to the canal direction was 25.0 degrees how much work (in KJ) does the horse do in 9.1 minutes?
Started by ajackson ( Lanier Technical College )
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We can use the formula W = F x d x cos(theta) to calculate the work done by the horse in 9.1 minutes. First, we will convert 12.80 Km/hr to m/s. This can be done by dividing 12.80 Km/hr by 3.6. This gives us 3.55 m/s. Next, we need to calculate the distance the horse has traveled in 9.1 minutes, which can be done by multiplying 3.55 m/s by 9.1 minutes. This gives us 32.18 meters. Finally, we can calculate the work done by the horse using the formula provided. The formula is W = F x d x cos (theta). This can be rearranged to obtain W = F x d x cos(25.0 degrees). Plugging in our values, we obtain W = 175 N x 32.18 m x cos (25.0 degrees). Simplifying, this gives us 455.9 J. Since we have the work in Joules, we can convert it to KJ by multiplying it by 1000. This gives us 455900 J, or 455.9 KJ. Therefore, the horse does 455.9 KJ of work in 9.1 minutes.

Answered by heather74

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