Physics
You are holding a bulletin board weighing 6.46 N in place against a wall while your friend secures it to the wall. To keep it from slipping, you apply a force perpendicular to the bulletin board, pressing it directly into the wall. How large must this force be if the coefficient of static friction with the wall is 0.43?
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For the force to be able to hold the bulletin board in place against the wall, it must be equal or greater than the force of static friction (Fr). The magnitude of static friction is equal to the coefficient of static friction (μs) multiplied by the normal force (N), or Fr = μs * N. In this case, the normal force is equal to the weight of the bulletin board, 6.46 N. Thus, the force needed to keep the bulletin board from slipping is equal to 6.46 N * 0.43 = 2.77 N.
