physics

The second truck will move with the same velocity as the cannon after the collision. Since the cannon has a velocity of 0.8 m/s after the collision, the second truck will move at 0.8 m/s after the collision. The momentum of the system before the collision is equal to the momentum of the system after the collision, by the Law of Conservation of Momentum. The total momentum of the system before the collision is equal to the mass of the cannon times its velocity (600 kg x 240 m/s) plus the mass of the first truck times zero (400 kg x 0). After the collision, the total momentum is equal to the mass of the cannon times its velocity after the collision (600 kg x 0.8 m/s) plus the mass of the second truck times its velocity after the collision (400 kg x v). Setting the momentum before and after the collision equal to each other, we get: 600 kg x 240 m/s + 400 kg x 0 = 600 kg x 0.8 m/s + 400 kg x v Solving, we find that v = 0.8 m/s. Therefore, the second truck will move with a velocity of 0.8 m/s after the collision.