physics

A 53 kg bungee jumper jumps from a bridge. She is tied to a bungee cord whose unstretched length is 13 m, and falls a total of 35 m. Calculate the spring stiffness constant k of the bungee cord, assuming Hooke's law applies.

Answers

The spring stiffness constant (k) is calculated by dividing the force exerted by the bungee cord by the amount it stretches (displacement): k = F/x Since the force is the mass of the bungee jumper multiplied by the acceleration due to gravity (mg), and the displacement is the difference between the unstretched length of the bungee cord (13 m) and the total distance the bungee jumper fell (35 m) (x = 35 m - 13 m = 22 m): k = (53 kg (9.8 m/s2))/22 m k = 236.36 N/m Hooke’s law states that the force exerted by an elastic material (such as a bungee cord) is directly proportional to the amount it is stretched. Therefore, the spring stiffness constant (k) of the bungee cord can be calculated using the equation F = kx, where F is the force, k is the spring stiffness constant, and x is the displacement.

Answered by christopher99

We have mentors from

Contact support