physics
A 0.077-kg arrow is fired horizontally. The bowstring exerts an average force of 50 N on the arrow over a distance of 0.75 m. With what speed does the arrow leave the bow?
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The speed of the arrow can be calculated using the equation: V = F × D / m where V is the speed, F is the force, D is the distance, and m is the mass of the arrow. In this case, V = 50 N x 0.75 m / 0.077 kg = 658 m/s. This equation can be explained as follows: when a force is applied over a distance, work is done and energy is transferred to the object. If the mass is constant, then the energy transferred is equal to the force times the distance, and the velocity is equal to that energy divided by the mass. In other words, if more force is applied or a longer distance is covered, the velocity will be higher.
