Physics
A 63.0-kg bungee jumper is standing on a tall platform (h0 = 45.8 m). The bungee cord has an unstrained length of L0 = 9.18 m and, when stretched, behaves like an ideal spring with a spring constant of k = 67.2 N/m. The jumper falls from rest, and it is assumed that the only forces acting on him are his weight and, for the latter part of the descent, the elastic force of the bungee cord. Determine how far the bungee jumper is from the water when he reaches the lowest point in his fall.
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Answers
At the lowest point in his fall, the bungee jumper will be a distance L = L0 - (mg/k) below the surface of the water, where m is the jumper's mass (63 kg) and g is the acceleration due to gravity (9.8 m/s^2). Therefore, L = 9.18 - [(63 * 9.8) / 67.2] = 4.66 m below the surface of the water. The bungee jumper will be at a height of 45.8 - 4.66 = 41.14 m from the water.
