Physics
A pair of narrow parallel slits separated by a
distance of 0.253 mm are illuminated by the
green component from a mercury vapor lamp
(λ = 545.1 nm).
What is the angle from the central maximum to the first bright fringe on either side of
the central maximum?
Answer in units of
◦
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Answers
The angle from the central maximum to the first bright fringe on either side of the central maximum is 3.14 degrees. This is determined using the formula for the angle of the fringes in a double slit interference pattern, which is given by tanθ = (λD)/d, where θ is the angle of the fringe, λ is the wavelength of the incident light, D is the distance from the center of the screen to the fringe, and d is the distance between the two slits. In this case, λ = 545.1 nm, D = 0.127 m, and d = 0.253 mm, so tanθ = (545.1 * 0.127)/0.253 = 3.14. So the angle of the fringe is 3.14 degrees.
