Physics
A force of 60 N is exerted on one end of a 1.0-m-long lever. The other end of the lever is attached to a rotating rod that is perpendicular to the lever. By pushing down on the end of the lever, you can rotate the rod. If the force on the lever is exerted at an angle of 30degrees, what torque is exerted on the lever?
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Answers
The torque exerted on the lever is equal to the force multiplied by the lever's length, multiplied by the sine of the angle of the force. In this case, the torque is equal to (60 N)(1.0 m)(sin 30°), or 30 Nm. The torque is a measure of how much rotational force is applied to the lever, and is determined by multiplying the magnitude of the force, the length of the lever, and the sine of the angle of the force.
