physics
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. Unfortunately the archer stands on an elevated platform of unknown height. However, you find the arrow stuck in the ground 62.0 m away, making a 2.00 degree angle with the ground.
How fast was the arrow shooting?
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Answers
The arrow was travelling at a speed of approximately 765.3 m/s. This can be determined using the equation v^2 = u^2 + 2as, where the initial velocity (u) is 0, the acceleration (due to gravity) is 9.81 m/s^2 and the displacement (s) is calculated by taking the distance (62m) divided by the cosine of the angle of elevation (2 degrees) as the arrow was shot parallel to the ground. Plugging these values into the equation, we get v^2 = 0 + 2(9.81)(62/cos2), which gives us v = 765.3 m/s.
