physics

A baseball player pops a pitch straight up. The ball (mass 160 g) was traveling horizontally at 32.0 m/s just before contact with the bat, and 24.0 m/s just after contact. Determine the magnitude of the impulse delivered to the ball by the bat.

Answers

The magnitude of the impulse delivered to the ball by the bat is 32.0 - 24.0 = 8.0 kg m/s. This is the change in momentum that has been delivered to the ball by the bat. Since the velocity of the ball changed from a horizontal velocity to a vertical velocity, the force must have acted in the differential direction between the two velocities.

Answered by carpenterjacob

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