Physics

A 10 kg block is pushed across a rough surface by a 25N force the block moves at a constant velocity when this force is applied. A) determine the magnitude of the friction force acting on the block B) What is the coefficient of friction between the surface and the block

Answers

A) The magnitude of the friction force acting on the block is 25 N. B) The coefficient of friction between the surface and the block is 1.0. The coefficient of friction is calculated by dividing the force of friction (25 N) by the normal force (25 N). Since the friction force and normal force are equal, the coefficient of friction is 1.0.

Answered by lsantos

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