physics
A ball is tossed so that it bounces off the ground, rises to height of 2 m, and then hits the ground
again 0.75 m away from the first bounce.
a. How long is the ball in the air between the two bounces?
b. What is the velocity in the x-direction of the ball?
c. What is the speed of the ball just before the second bounce?
d. What is the angle of the velocity vector with respect to the ground right after its first bounce
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Answers
a. The time between the two bounces is 0.35 seconds. b. The velocity in the x-direction of the ball is 2.14 m/s. c. The speed of the ball just before the second bounce is 2 m/s. d. The angle of the velocity vector with respect to the ground right after its first bounce is 45 degrees. This is because the ball is moving at its maximum velocity when it reaches the peak of its trajectory and thus the angle between the velocity vector and the ground is 45 degrees.
