Physics
A particle's constant acceleration is south at 2.1 m/s2. At t = 0, its velocity is 45.2 m/s east. What is its velocity at t = 7.7 s? What's the magnitude and direction?
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The velocity of the particle at t = 7.7 s is 34.6 m/s east. The magnitude of the velocity is 34.6 m/s and the direction is east. This is because the particle is experiencing a constant southward acceleration of 2.1 m/s2, which is causing its eastward velocity to decrease by 10.6 m/s (45.2 m/s - (7.7 s * 2.1 m/s2)).
