Physics

Two blocks (one of which is on a ramp) are attached via a string looped over a pulley. The block on the incline has a mass of 5.0 kg; the block hanging downward (suspended by the pulley) has a mass of 7.0 kg. Assume the usual things (non-stretchy massless string, frictionless lightweight pully, air resistance / friction is negligible, etc.) What angle of incline (measured against the horizontal) allows the blocks to have constant velocity?

Answers

The angle of incline necessary for the blocks to have constant velocity can be determined using the equations of motion. For the inclined block, the equation of motion is written as: F_net = ma = mgsinθ - T Where T is the tension in the string. For the downward block, the equation of motion is written as: Fnet = ma = -T Setting the equations equal to each other and equating values, we get: mgsinθ - T = -T mgsinθ = 2T Thus, the tension in the string can be determined as: T = mgsinθ/2 For T to remain constant, sinθ must remain constant. This implies that the angle of incline must remain constant for the blocks to have constant velocity. Therefore, the angle of incline necessary for the blocks to have constant velocity is 45 degrees (since sin 45 = 1).

Answered by Leslie

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