physics
A(n) 11 g bullet is fired into a(n) 111 g block
of wood at rest on a horizontal surface and
stays inside. After impact, the block slides
14 m before coming to rest.
The acceleration of gravity is 9.8 m/s
If the coefficient of friction between the
surface and the block is 0.7, find the speed of
the bullet before impact.
Answer in units of m/s
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Answers
The speed of the bullet before impact is determined using the conservation of momentum. The block has an initial momentum of 0, and the bullet has an initial momentum equal to the momentum of the block after impact. Conservation of momentum states that the sum of the initial momenta of the system must equal the sum of the final momenta of the system. Momentum = mass x velocity v_bullet = (m_block * v_block_final - m_block * 0) / m_bullet v_bullet = (111g * 14m/s) / 11g v_bullet = 12.727 m/s
