physics
A box having a mass of 50kg is dragged across a horizontal floor by means of a rope tied on the front of it. The coefficient of friction between the box and the floor is .3. If the angle between the rope and the floor is 30 degrees, what force must be excerted on the rope to move the box at uniform speed?
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The force required to move the box at uniform speed would be the weight of the box (50kg x 9.8 m/s2 = 490 N) multiplied by the coefficient of friction (0.3). The force would also be dependent on the angle of the rope. If the angle was 30 degrees, then the downward component of the rope force would be 490N x 0.86 = 423N. Therefore, the force required to move the box at uniform speed would be 423N.
