physics

a 60 kilogram student sitting on a hardwood floor accelerates at 1.3 meters per second squared when pulled by a 240 newton horizontal force. what is the coefficient of friction between the student and the floor?

Answers

The coefficient of friction is the ratio of the force of friction to the normal force (or weight) of the student. Using the equation Ff = μ*Fn, we can calculate the coefficient of friction: Ff = 240 N Fn = 60 kg * 9.8 m/s2 = 588 N μ = Ff / Fn = 240 N / 588 N = 0.41 The coefficient of friction is 0.41, which indicates that the floor offers medium friction to the student's movement.

Answered by Thomas Brown

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