Physics

The water in a river flows uniformly at a constant speed of 2.53 m/s between parallel banks 69.8 m apart. You are to deliver a package directly across the river, but you can swim only at 1.74 m/s. (a) If you choose to minimize the time you spend in the water, in what direction should you head? ____° from the direction of the stream (b) How far downstream will you be carried? ______m (c) If you choose to minimize the distance downstream that the river carries you, in what direction should you head? ____° from the direction of the stream (d) How far downstream will you be carried? _____m ----------------- I know we're dealing with motion in 2D, but I don't even know which equations to use or how to start. Any help or jumpstarts will be greatly appreciated.

Answers

The underlying idea in this problem is the concept of vector addition and resolution. Since the river is flowing at a constant speed in one direction said direction is known as the "x-direction" while the direction of your swim is the " y-direction." The river is flowing at a constant rate of 2.53 m/s in the x-direction. This is your vector vx. You are swimming at 1.74 m/s in the y-direction. This is your vector vy. To find the direction you need to swim, to minimize the time spent in the water, you need to solve for the angle θ using the equation: θ = tan-1 (vy/vx) The angle θ = tan-1 (1.74/2.53) = ~37.7° from the direction of the stream. To find the distance downstream carried, you can use the equation: Distance downstream = vx * time Where time is the time taken to cover the distance of 69.8 m across the river. To solve for time you can use the equation: time = s/v Where s is the distance across the river (69.8 m) and v is the combined velocity

Answered by kyle32

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