PHYSICS

a 0.1 kg mass is suspended at rest from a spring near the Earth's surface, the distance that the spring is stretched is measured to be 1.0 cm. What is the spring constant of the spring (remember the MKS units)? A mass of 2 kg is attached to a spring with constant 18 N/m. How far is the spring stretched? A spring with a spring constant of 28.9 N/m is attached to different masses, and is stretched 5cm. What is the force exerted on the spring?

Answers

The force exerted on the spring is determined by Hooke's Law, which states that F = kx, where F is the force exerted on the spring and k is the spring constant (in this case, 28.9 N/m). Therefore, the force exerted on the spring is equal to the spring constant multiplied by the distance it is stretched (5 cm), resulting in a force of 144.5 N.

Answered by hardyedgar

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