Physics
A hockey player shoots the puck which is initially at rest by applying a force of 72 N through a displacement of 1.6 m. The mass of the puck is 161 grams.
a) Calculate the work done by the player on the puck.
b) Calculate the resulting speed of the puck
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Answers
a) The work done by the player on the puck can be calculated using the equation W = F∙d = 72 N ∙ 1.6 m = 115.2 N∙m. b) The resulting speed of the puck can be calculated using the equation W = F∙d = ½ mv2, where m is the mass of the puck and v is the speed of the puck. Rearranging for speed, v = (2W/m)1/2. Substituting in the values gives v = (2(115.2 N∙m)/(0.161 kg))1/2 = 12.6 m/s. This is the resulting speed of the puck due to the work done by the player in shooting it.
