physics

A hockey puck of mass 0.27 kg is sliding along a slippery frozen lake, with an initial speed of 56 m/s. The coefficient of friction between the ice and the puck is μK = 0.032. Friction eventually causes the puck to slide to a stop. Find the work done by friction.

Answers

The work done by friction is given by Wfriction = μK Fs, where Fs is the frictional force and μK is the coefficient of kinetic friction between the puck and the ice. Since the force of friction is equal to μK multiplied by the normal force between the puck and the ice, the total work done by friction is Wfriction = μK (mg)s, where m is the mass of the puck and s is the distance traveled by the puck. Therefore, the work done by friction can be calculated as Wfriction = (0.032)(0.27 kg)(9.81 m/s2)s, where s is the distance traveled by the puck. Since the puck is eventually brought to a stop, s = 56 m/s. Plugging in these values, we get Wfriction = 13.08 J. Therefore, the work done by friction to bring the hockey puck to a stop is 13.08 J.

Answered by Jose

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