Physics

A 1000-kg car is driving toward the north along a straight road at a speed of 20.0 m/s. The driver applies the brakes and the car comes to a rest in a distance of 140 m. What is the constant force applied to the car to bring it to rest?

Answers

The constant force applied to the car to bring it to rest is the force of kinetic friction between the tires of the car and the road surface. This force can be calculated using the following equation: F = ma where F is the force, m is the mass of the car (1000 kg), and a is the acceleration. The acceleration can be calculated using the equation: a = (Vf - Vi) / t where Vf is the final velocity (0 m/s), Vi is the initial velocity (20 m/s), and t is the time taken to bring the car to rest. The time taken can be calculated using the equation: t = d / vi where d is the distance traveled (140 m), and vi is the initial velocity (20 m/s). Substituting the values in the above equations, we get: a = (0 - 20) / (140/20) = -1 m/s² F = 1000 x (-1) N = -1000 N Therefore, the constant force applied to the car to bring it to rest is -1000 N.

Answered by petersonsierra

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