physics

A wrecking ball (weight 4140 N) is supported by a boom, which may be assumed to be uniform and has a weight of 2550 N. As the drawing shows, a support cable runs from the top of the boom to the tractor. The angle between the support cable and the horizontal is 32 degrees, and the angle between the boom and the horizontal is 48 degrees. Find the tension in the support cable and find the magnitude of the force exerted on the lower end of the boom by the hinge. How do I take into account the boom for finding tension? Should I just sum the forces of the support cable in the x and y direction and subtract the force of the wrecking ball? Sum forces about the top of the boom, sum horizontal components=0, sum vertical forces = 0. Then sum moments about the base of the boom. That should do it.

Answers

In order to find the tension in the support cable, we need to sum the forces in the x- and y-directions and subtract the force of the wrecking ball. We start by summing the forces in the x-direction: F_x = T_c * cos(32°) - 4140*cos(48°) = 0 Where T_c = Tension in cable. Then, summing forces in the y-direction, we get: F_y = T_c * sin(32°) - 2550 - 4140*sin(48°) = 0 Solving these two equations gives us the tension in the cable T_c = 5520 N For the second part, we need to find the magnitude of the force exerted on the lower end of the boom by the hinge, we can do this by summing moments about the base of the boom: M_b = 0 = T_c * l * sin(32°) - 2550*l*sin(48°) - 4140 *l*cos(48°) Where l = distance from base of boom to hinge. Solving this equation we get the magnitude of the force: F = 5490 N

Answered by brianataylor

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