physics

A 3 meter tall 40 degree inclined plane with a coefficient of friction of .3 with a box sliding from its top has this acceleration and final velocity.

Answers

The acceleration of the box is just the coefficient of friction multiplied by the gravitational force: a = μ * g = 0.3 * 9.8 m/s2 = 2.94 m/s2 The final velocity of the box when it reaches the bottom of the inclined plane is the acceleration multiplied by the time it takes the box to travel that distance: v = at = 2.94 m/s2 * 3 m = 8.82 m/s

Answered by Megan Martinez

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