physics
An electron has an initial speed of 178000 m/s. If it undergoes an acceleration of 4.8 x 1014 m/s2, how far has it traveled before reaching a speed of 789000 m/s? Answer in units of m.
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The distance traveled can be calculated by integrating the acceleration with respect to speed. This gives us the equation: distance = time * (initial velocity + final velocity) / 2. We know the initial velocity (178000 m/s), the final velocity (78900 m/s) and the acceleration (4.8 x 1014 m/s2). We also know that the time needed to change the velocity is equal to (final velocity - initial velocity) / acceleration: Time = (78900 m/s - 178000 m/s) / (4.8 x 1014 m/s2) = 0.02317 s Therefore, the distance traveled is: Distance = 0.02317 s * (178000 m/s + 78900 m/s) / 2 = 854.8 m
