physics PLEASE help

A 5.0-kg block is at rest on a horizontal floor. If you push horizontally on the 5.0-kg block with a force of 10.0 N, it just starts to move. (a) What is the coefficient of static friction? (b) A 12.0-kg block is stacked on top of the 5.0-kg block. What is the magnitude F of the force, acting horizontally on the 5.0-kg block as before, that is required to make the two blocks start to move?

Answers

(a) The coefficient of static friction is 2.0. (b) The force required to make the two blocks start to move is 20 N. This is because the net force acting on the combined 17 kg needs to be greater than the force of friction the combined blocks experience, which is equal to the product of the coefficient of static friction and mass of the two blocks (2 × 17 = 34 N). Therefore, the force required to make the two blocks start to move is the total mass of the two blocks multiplied by the coefficient of static friction (17 × 2 = 20 N).

Answered by qpotter

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