Physics (Mechanics)

The maximum velocity of the moving electron is determined using the equation v^2 = 2as, where a is the acceleration. This can be rearranged to obtain: a = v^2/2s The acceleration of the movable electron is given by the force equation, above. Solving for a we get: a = (2.3E-28/r^2)/(9.1E-31) Substituting r = 7.1E-10 m gives a = 4.81E17 m/s^2 Using the equation for a, the maximum velocity of the moving electron becomes: v = sqrt(2*4.81E17*7.1E-10) v = 3.87E7 m/s Therefore, the maximum velocity of the moving electron after release is 3.87E7 meters per second. This result makes sense because the force on the movable electron is an attractive force, and thus accelerates the movable electron towards the fixed electron. As the distance between the electrons decreases, the acceleration increases, leading to a larger maximum velocity of the movable electron after release.