physics help
a particle moves uniformly around the circumference of a circle whose radius is 8 cm with a period of pi/20 s. the angular velocity w of the particle is
a. 2.5 rad/s
b. 3.2 X 10^2 rad/s
c. 40 rad/s
d. 7.9 rad/s
e. 96 rad/s
please explain
thanks!
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Answers
Answer: d. 7.9 rad/s Explanation: The angular velocity is related to the period and the radius of the circle. The angular velocity is equal to 2π divided by the period, multiplied by the radius. Thus, the angular velocity of the particle is w = [2π/ (π/20)] * 8 cm = 2π * 8 cm / (π/20) = 2π * 8 cm / (π/20) = 2π * 8 cm / 0.163 = 7.9 rad/s.
