physics help please
Answers
This is an example of an interference pattern due to sound waves generated from the two speakers. To find the points of minimum pressure amplitude, the distance from one speaker to the other (1.20 m) must be divided by the wavelength associated with a frequency of 870 Hz. To calculate the wavelength, use the equation: \lambda = \frac{v}{f} where \lambda is the wavelength, v is the speed of sound, and f is the frequency of the oscillator. In this case, v = 343 m/s and f = 870 Hz, so the wavelength associated with the oscillator is: \lambda = \frac{343 \; m/s}{870 \, Hz} \approx 0.395 \; m To find the points of minimum pressure amplitude, divide the distance between the two speakers (1.20 m) by the wavelength (0.395 m). The result is 3.03, which means that the points of minimum pressure amplitude will be located 3.03 wavelengths away from the origin speaker. This equivalent to 1.20 m / 0.395 m = 3.03, so the points of minimum pressure amplitude will be located at 1.20 m / 3.03 = 0.398 m, 0.799 m, and 1.20 m away from the origin speaker. Therefore, the points of minimum pressure amplitude are located at 0.398 m, 0