Physics 102 (College)
I'm stuck on part B of this question:
A system does 125 J of work on environment and gains 79 J of heat in the process. Find change in internal energy (delta U, abbreviated dU)of
a. the system and b. the environment.
A. Find dU of the system
W = 125 J
Q = 79 J
dU = Q - W
dU = (79 J - 125 J) = -46.0 J
B. find dU of the environment
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Answers
Since the same amount of energy is gained by the environment as is done by the system, then the change in internal energy of the environment is equal to the change in internal energy of the system. dU = -46.0 J