Math
In an A.P.the third term is 4 times the first term and the 6th term is 17. Find the series
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Let the first term be 'a', then the third term = 4a and the 6th term = 17 The common difference, d = a + 4a + 4a + 4a = 9a Therefore, the A.P. = a, 4a, 17, 22 + 9a, 31 + 9a, 40 + 9a, ... = a, 4a, 17, 31, 40, 49, 58, 67, 76, ...
