math
In 2010 a city raised $5,999,400 in tax revenue by charging each taxpayer the same amount. For 2011 there has been a net loss of 12 taxpayers, necessitating an increase fo $200 per taxpayer in order to maintain the tax revenue of $5,999,400. How many taxpayers were there in 2010?
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In 2010, there were 5,999,400 divided by the amount charged per taxpayer in order to maintain the same amount of tax revenue. This calculation would be: 5,999,400 / 200 = 29,997 taxpayers in 2010. To explain, there were 29,997 taxpayers in 2010, each paying the same amount, that resulted in a total tax revenue of $5,999,400. In 2011, there was a net loss of 12 taxpayers, necessitating an increase of $200 per taxpayer in order to maintain the same tax revenue of $5,999,400.
