MATH
I'm really confused how you do this
Two unequal semicircles, a square , and a rectangle are joined. If the dimensions of the rectangle are 8in by 16in, find the are of the entire region to the nearest 10th.
theres a rectangle in the middle and semi circle on top and side
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Answers
The area of the entire region can be calculated by adding together the area of the two semicircles, the square, and the rectangle. The area of the two semicircles can be calculated by multiplying π times the radius of each semicircle squared. The radius of each semicircle is equal to half the width of the rectangle (8in divided by 2). Therefore, the area of each semicircle is π(4in)^2, or approximately 50.27in^2. The area of the square is equal to the side length squared, which is 8in^2. The area of the rectangle is 8in times 16in, or 128in^2. Adding all of these together gives us a total area of 228.27in^2, which rounded to the nearest 10th is 228.3in^2.
