Math
John invested $2500, part at 8% and the rest at 12% per annum. The two parts earned equal amount of interest in one year. How much was invested at each rate?
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$1666.67 was invested at 8% and $833.33 was invested at 12%. This is because the total interest earned is equal for both parts of the investment. If x represents the amount invested at 8%, the amount invested at 12% is (2500-x). The interest earned after one year from the 8% investment is 0.08x and from the 12% investment is 0.12(2500-x). As the interest from both investments is equal, 0.08x = 0.12(2500-x). Solving this equation gives us x = 1666.67. Therefore, the amount invested at 8% is $1666.67 and the amount invested at 12% is $833.33.
