Math

4.905t^2 + 2.93t - 10 = 0 I have to solve for t. How do I solve this equation step by step? Thanks.

Answers

The equation is a quadratic equation of the form ax^2 + bx + c = 0. In order to solve for t, we can use the Quadratic Formula: t = [-b +/- sqrt(b^2-4ac)]/2a Where a = 4.905, b = 2.93, and c = -10. Substituting these values into the Quadratic Formula: t = [-2.93 +/- sqrt(2.93^2- 4(4.905)(-10))]/2(4.905) t = [-2.93 +/- sqrt(86.2025)]/9.81 t = [-2.93 +/- 9.29]/9.81 t = {-12.22/9.81, 6.39/9.81} t = {-1.244, 0.647}

Answered by jessica03

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