Math
Solve for x: 2sin^2x = 3sinx + 2 on
-pi < x < 4pi
(the "
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Answers
Yes, the complete set of solutions is -pi/6, 7pi/6, 11pi/6, 17pi/6, -5pi/6, 19pi/6, 23pi/6, and 29pi/6. To find these solutions, you need to factor the left side of the equation and set the factors equal to 0 and solve for x. After doing so, you'll have sin(x) = 0, 1/2 and -1. Translating this into x values, with the restriction that x is between -pi and 4pi, will give you the 8 solutions listed above.
