Math: Calculus
Assume that a population size at time t is N(t) and that N(t)=40 x 2^t , t>0.
Show that N(t)=40e^t ln2
Can someone please guide me step by step on this question? Im really confused. thanks.
I tried to work it out, and this is what I got.
N(t)= 40 x 2^t
= 40 x ln 2^t
= 40 x t ln 2
Reply
Answers
Using the laws of exponents and logarithms, we can rewrite N(t) as follows: N(t) = 40 x ln 2^t = 40 x ln (e^t) (since 2^t = e^t ln2) = 40 x tln2 (since ln(e^t) = t) = 40e^t ln2
