calculus
how to simplify:
((9^x * 3^2 * (1/3^-x)) - 27^x ) / 3^(3x) * 9
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Answers
The expression can be simplified as follows:
((9^x * 3^2 * (1/3^-x)) - 27^x ) / 3^(3x) * 9 = (9^x * 3^2 * 3^x - 27^x ) / 3^(4x) * 9
= (9^x * 3^(2+x) - 27^x ) / 3^(4x) * 9
= (9^x * 3^(x+2) - 27^x ) / 3^(4x) * 9
= (9^x * 3^x * 3^2 - 27^x ) / 3^(4x) * 9
= (9^x * 3^x * 9 - 27^x ) / 3^(4x) * 9
= (9^x * 9^2 - 27^x ) / 3^(4x) * 9
= (9^(x+2) - 27^x ) / 3^(4x) * 9
= (9^2 * 9^x - 27^x ) / 3^(4x) * 9
= (81 * 9^x - 27^x ) / 3^(4x) * 9
= (81 *