Computer Science Homework

# Assignment 2.1 - combining concepts.py # By _____, _____, and _____ # 10 points # this is a partner assignment (group size 1-3) # being able to take 2 (or more) separate programs that you have found or solved # and combining them into a single working program is an important skill # rule - begin with your assignment: formula from last week (or a new formula if you prefer) # rule - add to this: a functioning "do you want to use this again [yes/no] feature" # rule - add to this: only accepting "yes"/"no" responses and otherwise re-asking # challenge - also include a menu of multiple formula options # sub challenge - ...and only accept legal choices from this menu of options # challenge - there is no limit to how complex your formulae may be # note - it is OK to "copy" from examples we've seen ("copy" means "use as guidance"), # feel free to refer to the example files in this chapter # correctly assembling together features from those example files is your challenge here # this is a good time to think about "compehensive testing"... # be sure your code works for "yes", "no", "illegal response"... # most simple example (contains complex formula & repitition) print ("version 1") print ('includes small error - a "no" response ends the program, "yes" OR ANY OTHER RESPONSE continues the program') counter = 1 playing = True while playing: print ("this will solve the distance formula for 2 points: (x1, y1) & (x2, y2)") x1 = float(input("please enter x1: ")) y1 = float(input("please enter y1: ")) x2 = float(input("please enter x2: ")) y2 = float(input("please enter y2: ")) ans = ((x2 - x1) ** 2 + (y2 - y1) ** 2) ** .5 print ("the distance between those 2 points is",ans) ans = input("want to play again? enter yes or no: ") if ans == "no": playing = False print ("done, thank you.") print ("\n \n \n") # more simple example (contains simple formula, repitition, & only accepts yes/no) # this is somewhat ugly - we've "pasted" "menu choices" and "play again" together... # correctly. It works but it isn't easy to read print ("version 2a - fully functioning") playing = True while playing: print ("this will solve the distance formula for 2 points: (x1, y1) & (x2, y2)") x1 = float(input("please enter x1: ")) y1 = float(input("please enter y1: ")) x2 = float(input("please enter x2: ")) y2 = float(input("please enter y2: ")) ans = ((x2 - x1) ** 2 + (y2 - y1) ** 2) ** .5 while True: response = input("do you want to play again (yes or no)?: ").lower() if (response == "yes") or (response == "no"): break else: print ("illegal response, try again") if response == "no": print ("thank you, bye") playing = False print ("\n \n \n") # more elegant example # this combines our functionalities in a more clean and elegant way... # than the previous example, although it is not as direct a "copy/paste"... # as the previous example print ("version 2b - fully functioning") while True: answer = input("would you like to solve the distance formula (yes/no)? ").lower() if answer == "yes": x1 = float(input("please enter x1: ")) y1 = float(input("please enter y1: ")) x2 = float(input("please enter x2: ")) y2 = float(input("please enter y2: ")) ans = ((x2 - x1) ** 2 + (y2 - y1) ** 2) ** .5 if answer == "no": break print ("thank you, bye") print ("\n \n \n") # complex example (contains complex formula, repitition, & only accepts yes/no) print ("version 3 - fully functioning") while True: goal=int(input("what # prime would you like me to find? ")) counter = 0 testnum = 1 while counter < goal: testnum = testnum + 1 answer = "prime" for divtest in range (2,testnum): if testnum % divtest == 0: answer = "not prime" if answer == "prime": counter = counter + 1 print (testnum,"is prime number",counter) invalid = True while invalid: response = input("would you like to do this again: yes or no? ") if response == "yes" or response == "no": invalid = False else: print ("illegal response, please try again") if response == "no": print ("thanks, bye.") break print ("\n \n \n") # most complex example (contains menu of formulae, repition, and only accepts correct choices) # draft - partially complete # notice how this drafting process helps us understand how a large, complex program # can be built from simple parts print ("version 4 - partial draft - using break") # this "partial draft" is an example of a well-organized # drafting process that can make creating large and complex code more simple while True: print ("would you like to calculate a distance, a midpoint, a square root, or stop") response = input("please enter DIST, MID, ROOT, or STOP: ").lower() if response == "dist" or response == "mid" or response == "root" or response =="stop": invalid = False if response == "stop": break if response == "dist": print ("do dist") #insert dist formula code here if response == "mid": print ("do mid") #insert midpoint formula code here if response == "root": print ("do root") #insert root code here print ("thanks, bye") print ("\n \n \n") # most complex example (contains menu of formulae, repition, and only accepts correct choices) print ("version 4 - final draft - using break") while True: print ("would you like to calculate a distance, a midpoint, a square root, or stop?") response = input("please enter DIST, MID, ROOT, or STOP: ").lower() if response == "dist" or response == "mid" or response == "root" or response =="stop": invalid = False if response == "stop": print ("thanks, bye") break if response == "dist": print ("this will solve the distance formula for 2 points: (x1, y1) & (x2, y2)") x1 = float(input("please enter x1: ")) y1 = float(input("please enter y1: ")) x2 = float(input("please enter x2: ")) y2 = float(input("please enter y2: ")) ans = ((x2 - x1) ** 2 + (y2 - y1) ** 2) ** .5 print ("the distance between those 2 points is",ans) if response == "mid": print ("This program will evaluate the midpoint formula using two points (x1,y1) and (x2,y2)") x1 = float(input("what is the value of x1? ")) y1 = float(input("what is the value of y1? ")) x2 = float(input("what is the value of x2? ")) y2 = float(input("what is the value of y2? ")) x3 = (x1 + x2) / 2 x3 = round(x3, 2) y3 = (y1 + y2) / 2 y3 = round(y3, 2) print ("\n") print ("the midpoint is approximately (", x3, ",", y3, ")") if response == "root": num = float(input("what number would you like me to find the square root of? ")) testing = 0 while testing * testing < num: testing += .001 print (round(testing, 2))