Chemistry
How much energy will be liberated upon the combustion of 12.5 grams of ethene?
C2H4(g) + 3O2(g) ----> 2CO2(g) + 2H2O(g)
Delta H = -1387.4 kj
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Answers
The amount of energy liberated upon the combustion of 12.5 grams of ethene is computed by taking the enthalpy of combustion of ethene multiplied by the moles of the substance burned.
The molar mass of ethene is 28.05 g/mol, so the number of moles of ethene burned is 0.445 mol.
Therefore, the amount of energy liberated is -1387.4 kJ/mol * 0.445 mol = -618.88 kJ.
