Calculus
A voltage V across a resistance R generates a current I=VR. If a constant voltage of 4 volts is put across a resistance that is increasing at a rate of 0.3 ohms per second when the resistance is 4 ohms, at what rate is the current changing? (Give units.)
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Answers
The rate of change of the current is 0.9 amperes per second (A/s). This is because the resistance is increasing at a rate of 0.3 ohms per second. This means that as the resistance increases, the current will increase proportionately. Therefore, the current is changing at a rate of 0.3 Ω/s x 4 V/Ω = 0.9 A/s.
