calculus
evaluate if possible the function at the given values(s) of the independent variable. Simplify the results.
f(x)= square root x+5
(a) f(-4)
(b) f(11)
(c) f(-8)
(d) f(x+deltax)
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Answers
(a) f(-4)= square root (-4)+5=√1+5=2 (b) f(11)= square root 11+5=√16+5=5+√16 (c) f(-8)= square root (-8)+5=√7+5= -1+√7 (d) f(x+deltax)=square root (x+deltax)+5. This is because we would just add the number inside the square root with 5.
