calculus
if f is a continuous function defined by f(x)={x^2+bx, 5 sin("pie"/2x) then b= ?
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b=0. In this case, the function f(x) is a combination of two different polynomials, each with a degree of 2. Since the two polynomials do not share any common terms, the coefficient of x in each must be equal, thus b = 0.
