Calculus
y = ln(3x+5), then d^2y/dx^2 =
a. 3/(3x+5)
b. 3/((3x+5)^2)
c. 9/((3x+5)^2)
d. -9/((3x+5)^2)
e. -3/((3x+5)^2)
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Answers
Answer: e. -3/((3x+5)^2). The second derivative of y must first be derived from the natural logarithm function. Applying the chain rule, d^2y/dx^2 = (d/dx)(dy/dx) = d^2/dx^2 (3x+5) = -3/((3x+5)^2).
