calculus
A 29-ft chain with mass density 3 lb/ft is initially coiled on the ground. How much work is performed in lifting the chain so that it is fully extended (and one end touches the ground).
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The work done in lifting the chain so that it is fully extended is W = mgΔh where m is the mass of the chain, g is the acceleration due to gravity (9.8 m/s2), and Δh is the change in height. The mass of the chain is m = 29 ft × 3 lb/ft = 87 lb The change in height is Δh = 29 ft Therefore, the work done is W = 87 lb × 9.8 m/s2 × 29 ft = 2,431.6 lb-ft.
